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Also, look for videos by Kahn Academy. (a) + 2 (b) +4 (c) +1 (d) +3 Answer: Question 18. Balance the atoms undergoing change in the Oxidation number. (b) List three measures used to prevent rusting of iron. Question 2. b. Cu + HNO3 Cu2+ + NO + H2O The reaction occurs in acidic solution. Example #1: Here is the half-reaction to be considered: MnO 4 ¯ ---> Mn 2+ It is to be balanced in acidic solution. The Half-Reaction Method: In balancing the redox reaction in acid conditions, we can add {eq}\rm H^+/H_2O {/eq} liberally. Answer: Let the oxidation number of S in H2SO4 be x. The Previous answer is noy balanced !! Answer: (a) Ag+  is reduced, C6H6O2 is oxidised.Ag+  is oxidising agent whereas C6H6O2 is reducing agent. of O is zero. Balance the following redox reactions by ion-electron method. Therefore, O3 acts only as an oxidant. Answer: (a) The oxidation number of nitrogen in HNO3 is +5 thus increase in oxidation number +5 does not occur hence HNO3 cannot act as reducing agent but acts as an oxidising agent. Thus, when electricity is passed, Ag+(aq) ions move towards the cathode while NO3– ions move towards the anode. Question 2. MnO4 (aq) + Fe (s) --> Mn2+ (aq) +Fe2+ (aq) chemistry Cr3+/Cr = -0.74 V. Arrange these metals in increasing order of their reducing power. (b) When cone. Phases are optional. Dr.Bobb222 please help balance the following oxidation-reduction reactions, which occur in acidic solution, using the half-reaction method. Question 9. Why it is more appropriate to write these reactions as: WARNING: This is a long answer. Question 6. ∴ 4I⁻ + MnO₄  + 2H₂O ---------- I₂  +  MnO₂  + 4OH⁻. Each half-reaction is balanced separately and then the equations are added together to give a balanced overall reaction. Balance each half reaction. Question 3.Which of the following is most powerful oxidizing agent in the following. answered Feb 14 by ... Balance MnO4^- + Fe^2+ → Fe^3+ + Mn^2+ in acidic medium by ion electron method. If, however, excess of Cl2 is used, the initially formed PCl3 reacts further to form PCl5 in which the oxidation state of P is +5 = +1) group, therefore, O.N. Question 19. Each of these half-reactions is balanced separately and then combined to give the balanced redox equation. Further show: Since the electrode potential (i.e., reduction potential of Ag+(aq) ions is higher than that of H2O molecules, therefore, at the cathode, it is the Ag+(aq) ions (rather than H2O molecules) which are reduced. Further, H is added to BCl3 but is removed from LiAlH4, therefore, BC13 is reduced while LiAlH4 is oxidised. The Half-Reaction Method . When the given electrode acts as anode SHE, we give -ve sign to its reduction potential and +ve sign to its oxidation potential. (b) H3P02(aq) + 2CuS04(aq) + 2H2O(l) ————->H3P04(aq) + 2Cu(s) + H2S04(aq) Balance the Following Redox Reactions by Ion-electron Method: CBSE CBSE (Science) Class 11. (ii) by 2 and add, we have, of Fe decreases from +3 if Fe2O3 to 0 in Fe while that of C increases from +2 in CO to +4 in CO2. But the oxidation number cannot be fractional. Fluorine reacts with ice and results in the change: If, however, excess of O2 is used, the initially formed CO gets oxidised to CO2 in which oxidation state of C is + 4. (i) KMnO4 (ii) K2Cr2O7 (iii) KClO4 Thus, HI is a stronger reductant than HBr. As a result, O2 is liberated at the anode according to equation (iv). (b) MnO4–(aq) + S02(g) ——-> Mn2+(aq) +H2S04–(in acidic solution) (a) Arrange the following in order of increasing O.N of iodine: Question 2. In the ion-electron method (also called the half-reaction method), the redox equation is separated into two half-equations - one for oxidation and one for reduction. 1. Balance the following equation in basic medium by ion electron method and oxidation number method and identify the oxidising agent and the reducing agent. (a)Give two important functions of salt bridge. Here, the O.N. It is VERY easy to balance for atoms only, forgetting to check the charge. Question 6. Write a balanced redox equation for the reaction. ∴ General Steps ⇒ Step 1. Present a balanced equation for the reaction for this redox change taking place in water. 2Cu2+(aq) + 4I–(aq) >Cu2I2(s) + I2(aq); Cu2+(aq) + 2Br–> No reaction. (iv) In aqueous solution, CuCl2 ionises as follows: Question 7. 1 Answer +1 vote . Using the standard electrode potentials given in the Table 8.1, predict if the reaction between the following is feasible: Write the oxidation number of each atom its symbol. Answer: Question 9. Suggest structure of these compounds. The ion-electron method allows one to balance redox reactions regardless of their complexity. He discusses balancing via the oxidation number method as well as ion-electron (also called half-reaction). (d) Answer: Question 22. Question 23. 2 (+1) + x + 4 (-2) = 0 x – 6 = 0 x — +6 Answer: A standard hydrogen electrode is called reversible electrode because it can react both as anode as well as cathode in an electrochemical cell. (d) C6H5CHO(l) + 2Cu2+(aq) + 5OH–(aq) ———–> No change observed Now, Balance the charges by adding water and Hydrogen ions. Why? Question 7. Suggest structure of these compounds. from zero to -1 or -2, but cannot increase to +2. (a) an oxidizing agent (b) a reducing agent Here, O.N. Answer: Question 17. For what purpose it is used? Similarly, at the anode, either Cl–(aq) ions or H2O molecules are oxidised. Answer: Each of these half-reactions is balanced separately and then combined to give the balanced redox equation. Oxidation half equation: Arrange the following metals in the order in which they displace each other from the solution of their salts.Al, Cu, Fe, Mg and Zn. Question 7. Multiply Eq. Calculate the sum of the oxidation numbers of all the atoms. For a particular redox reaction Cr is oxidized to CrO42– and Fe3 is reduced to Fe2 . (b) N2H4(l) + ClO–(aq) ——–> NO(g) + CV(aq) of -2 and maximum of +6. or an oxidation state of +1 compounds of I with more electronegative elements, i.e., O, F, etc.) Question 1. We want the net charge and number of ions to be equal on both sides of the final balanced equation. (b) Cr is negative electrode, Pt in Mn04_ acts as positive electrode. Answer: The given redox reaction is Zn(s) + 2Ag+(aq) ——————-> Zn2+(aq) + 2Ag(s) (a) P4(s) + OH–(aq) ———> PH3(g) + H2PO2–(aq) (b) ClO4 – does not show disproportionation reaction. 8.18 Balance the following redox reactions by ion – electron method (b) (In Acidic medium) CU2++ 2e– ———> Cu(s); E° = +0.34 V Refer to the periodic table given in your book and now answer the following questions. Reduction half equation: 2Ag + 2H2 S04 ———-> Ag2 S04 + 2H20 + S02 (i) Permanganate ion (MnO4-) reacts with sulphur dioxide gas in acidic medium to produce Mn2+ and hydrogen sulphate ion. Step3. Question Bank Solutions 9919. Recall that a half-reaction is either the oxidation or reduction that occurs, treated separately. Question 3. Imagine that it was an acidic solution and use H+ and H2O to balance the oxygen atoms in each half-reaction. Use this online balancing redox reactions calculator to find the balancing redox reactions using half reaction method. In principle, O can have a minimum O.N. 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